{"id":14,"date":"2018-11-21T21:10:00","date_gmt":"2018-11-21T20:10:00","guid":{"rendered":""},"modified":"2020-08-22T14:26:51","modified_gmt":"2020-08-22T12:26:51","slug":"datarmatics-researchers-decimate-biscuit-and-banana-puzzle","status":"publish","type":"post","link":"https:\/\/kindsonthegenius.com\/blog\/datarmatics-researchers-decimate-biscuit-and-banana-puzzle\/","title":{"rendered":"Datarmatics Researchers Decimate Biscuit-and-Banana Puzzle"},"content":{"rendered":"<div style=\"clear: both; text-align: center;\">\n<p><a style=\"margin-left: 1em; margin-right: 1em;\" href=\"https:\/\/kindsonthegenius.com\/blog\/wp-content\/uploads\/2018\/11\/Biscuit-2Band-2BBanana-2BPuzzle2.jpg\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/kindsonthegenius.com\/blog\/wp-content\/uploads\/2018\/11\/Biscuit-2Band-2BBanana-2BPuzzle2-300x286.jpg\" width=\"320\" height=\"305\" border=\"0\" data-original-height=\"733\" data-original-width=\"768\" \/><\/a><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<p><b><span style=\"font-size: large;\">Dr. Wonu Nduka<\/span><\/b><br \/>\nMathematically!\ud83d\ude01<\/p>\n<p>Let the biscuit be &#8220;x&#8221;<br \/>\nlet banana be &#8220;y&#8221; and<br \/>\nLet lollipop be &#8220;z&#8221;<\/p>\n<p>Such that the pictorial equations can be transformed into algebraic equations,\u00a0 thus:<\/p>\n<p>x+x+x=30&#8230;..(1)<br \/>\ny+y+x=14&#8230;..(2)<br \/>\ny+z+z=8&#8230;&#8230;.(3)<br \/>\n&#8216;z&#8217;+0.5y+0.5y&#8217;x&#8217;=?&#8230;..(4)<\/p>\n<p>Equations 1, 2 &amp;3 could further be reduced to:<\/p>\n<p>3x=30&#8230;&#8230;..(5)<br \/>\nx+2y=14&#8230;.(6)<br \/>\ny+2z=8&#8230;&#8230;(7)<\/p>\n<p>From equation (5) we have:<br \/>\n3x=30<br \/>\nx=10<br \/>\nsubstitute x=10 in equation (6)<br \/>\n2y+10=14<br \/>\n2y+10-10=14-10<br \/>\n2y=4<br \/>\ny=2<\/p>\n<p>Now, substitute y=2 in equation (7)<br \/>\ny+2z=8<br \/>\n2-2+2z=8-2<br \/>\n2z=6<br \/>\nz=3<\/p>\n<p>To evaluate the expression (4), where x=10, y=2 and z=3.<br \/>\nThis is the overarching part of the problem-solving episode.<\/p>\n<p>Considering the time, the fingers of the banana and the number of dots on the biscuits.<\/p>\n<p>If x=10 when dots were 10, then x=7, when dots became 7.<\/p>\n<p>If y=2 when we had two fingers of banana, then y=1 when the fingers of banana reduced to 1.<\/p>\n<p>If z=3, when the time was 3 o&#8217;clock, then z=2, when the time became 2 o&#8217;clock.<\/p>\n<p>When the logic above is being applied to the expression (4) we have:<br \/>\n\ud83d\udc47<br \/>\ny+yx+z<br \/>\n1+1*7+2<br \/>\n1+7+2=10<\/p>\n<p>EVALUATION<br \/>\nCheck using the previous equations, with x=10, y=2 and z=3<\/p>\n<p>x+x+x=30&#8230;..(1)<br \/>\ny+y+x=14&#8230;..(2)<br \/>\ny+z+z=8&#8230;&#8230;.(3)<\/p>\n<p>From equation (1)<br \/>\n10+10+10=30\u2705<\/p>\n<p>From equation (2)<br \/>\n2+2+10=14\u2705<\/p>\n<p>From equation (3)<br \/>\n2+3+3=8\u2705<\/p>\n<hr \/>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<div style=\"clear: both; text-align: center;\"><a style=\"margin-left: 1em; margin-right: 1em;\" href=\"https:\/\/kindsonthegenius.com\/blog\/wp-content\/uploads\/2018\/11\/Biscuit-2Band-2BBanana-2BPuzzle2-1.jpg\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/kindsonthegenius.com\/blog\/wp-content\/uploads\/2018\/11\/Biscuit-2Band-2BBanana-2BPuzzle2-1-300x286.jpg\" width=\"320\" height=\"305\" border=\"0\" data-original-height=\"733\" data-original-width=\"768\" \/><\/a><\/div>\n<p><span style=\"font-size: large;\"><b>Prof. Ebi Efebo<\/b><\/span><br \/>\nWe need to think outside the box<br \/>\nEach of the biscuits have 10 dots<br \/>\n3\u00d710=30<br \/>\nEach dot represents 1<br \/>\n2nd equation<br \/>\nEach finger of banana is\u00a0 1<br \/>\n2+ 2+10=14<br \/>\nEquation 3<br \/>\n2+3+3=8<br \/>\n2 fingers of banana and the 2 clocks at 3 o&#8217;clock\u00a0 each<br \/>\nEquation 4<br \/>\n2 o&#8217;clock+ 1 finger of banana + another finger of banana \u00d7 7 dots on the biscuits<br \/>\n2+1+1\u00d77<br \/>\nApplying BODMAS<br \/>\n7\u00d71+1+2<br \/>\n7+1+2=10<br \/>\nThat is the answer<\/p>\n<hr \/>\n","protected":false},"excerpt":{"rendered":"<p>&nbsp; Dr. Wonu Nduka Mathematically!\ud83d\ude01 Let the biscuit be &#8220;x&#8221; let banana be &#8220;y&#8221; and Let lollipop be &#8220;z&#8221; Such that the pictorial equations can &hellip; <\/p>\n","protected":false},"author":2,"featured_media":301,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0},"categories":[584],"tags":[],"_links":{"self":[{"href":"https:\/\/kindsonthegenius.com\/blog\/wp-json\/wp\/v2\/posts\/14"}],"collection":[{"href":"https:\/\/kindsonthegenius.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kindsonthegenius.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kindsonthegenius.com\/blog\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/kindsonthegenius.com\/blog\/wp-json\/wp\/v2\/comments?post=14"}],"version-history":[{"count":2,"href":"https:\/\/kindsonthegenius.com\/blog\/wp-json\/wp\/v2\/posts\/14\/revisions"}],"predecessor-version":[{"id":398,"href":"https:\/\/kindsonthegenius.com\/blog\/wp-json\/wp\/v2\/posts\/14\/revisions\/398"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/kindsonthegenius.com\/blog\/wp-json\/wp\/v2\/media\/301"}],"wp:attachment":[{"href":"https:\/\/kindsonthegenius.com\/blog\/wp-json\/wp\/v2\/media?parent=14"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kindsonthegenius.com\/blog\/wp-json\/wp\/v2\/categories?post=14"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kindsonthegenius.com\/blog\/wp-json\/wp\/v2\/tags?post=14"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}