**Dr. Wonu Nduka**

Mathematically!π

Let the biscuit be “x”

let banana be “y” and

Let lollipop be “z”

Such that the pictorial equations can be transformed into algebraic equations,Β thus:

x+x+x=30…..(1)

y+y+x=14…..(2)

y+z+z=8…….(3)

‘z’+0.5y+0.5y’x’=?…..(4)

Equations 1, 2 &3 could further be reduced to:

3x=30……..(5)

x+2y=14….(6)

y+2z=8……(7)

From equation (5) we have:

3x=30

x=10

substitute x=10 in equation (6)

2y+10=14

2y+10-10=14-10

2y=4

y=2

Now, substitute y=2 in equation (7)

y+2z=8

2-2+2z=8-2

2z=6

z=3

To evaluate the expression (4), where x=10, y=2 and z=3.

This is the overarching part of the problem-solving episode.

Considering the time, the fingers of the banana and the number of dots on the biscuits.

If x=10 when dots were 10, then x=7, when dots became 7.

If y=2 when we had two fingers of banana, then y=1 when the fingers of banana reduced to 1.

If z=3, when the time was 3 o’clock, then z=2, when the time became 2 o’clock.

When the logic above is being applied to the expression (4) we have:

π

y+yx+z

1+1*7+2

1+7+2=10

EVALUATION

Check using the previous equations, with x=10, y=2 and z=3

x+x+x=30…..(1)

y+y+x=14…..(2)

y+z+z=8…….(3)

From equation (1)

10+10+10=30β

From equation (2)

2+2+10=14β

From equation (3)

2+3+3=8β

**Prof. Ebi Efebo**

We need to think outside the box

Each of the biscuits have 10 dots

3Γ10=30

Each dot represents 1

2nd equation

Each finger of banana isΒ 1

2+ 2+10=14

Equation 3

2+3+3=8

2 fingers of banana and the 2 clocks at 3 o’clockΒ each

Equation 4

2 o’clock+ 1 finger of banana + another finger of banana Γ 7 dots on the biscuits

2+1+1Γ7

Applying BODMAS

7Γ1+1+2

7+1+2=10

That is the answer

The answer to #4 is 50.

Answer is 11